The number of bijective functions $f : \{1, 3, 5, 7, \ldots, 99\} \rightarrow \{2, 4, 6, 8, \ldots, 100\}$ such that $f(3) \geq f(9) \geq f(15) \geq f(21) \geq \ldots \geq f(99)$ is:

  • A
    $^{50}P_{17}$
  • B
    $^{50}P_{33}$
  • C
    $33! \times 17!$
  • D
    $\frac{50!}{2}$

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