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(D) For $n=4$,the subshells are $4s, 4p, 4d,$ and $4f$.The maximum number of electrons in these subshells are $2, 6, 10,$ and $14$ respectively.Since

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$16$

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(D) For $n=4$,the subshells are $4s, 4p, 4d,$ and $4f$.The maximum number of electrons in these subshells are $2, 6, 10,$ and $14$ respectively.Since all subshells are completely filled,the total number of electrons is $2 + 6 + 10 + 14 = 32$.In any completely filled subshell,exactly half of the electrons have $s=+\frac{1}{2}$ and the other half have $s=-\frac{1}{2}$.Therefore,the number of electrons with $s=+\frac{1}{2}$ is $\frac{32}{2} = 16$.Subshell$4s, 4p, 4d, 4f$Total $e^-$$2+6+10+14=32$Total $e^-$ with $s=+\frac{1}{2}$$1+3+5+7=16$Thus,the correct answer is $16$.

The number of electrons present in all the completely filled subshells having $n=4$ and $s=+\frac{1}{2}$ is . . . . . . . (Where $n=$ principal quantum number and $s=$ spin quantum number)

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