The number of isomers possible for the square | vedclass

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(C) The complex is $[PdClBr_2(SCN)]^{2-}$.For a square planar complex of the type $[Mabcd]$,there are $3$ geometrical isomers.However,here the ligand

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$4$

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(C) The complex is $[PdClBr_2(SCN)]^{2-}$.For a square planar complex of the type $[Mabcd]$,there are $3$ geometrical isomers.However,here the ligand $SCN^-$ is an ambidentate ligand,which can coordinate through $S$ (thiocyanate) or $N$ (isothiocyanate).For each geometrical isomer,linkage isomerism is possible.Specifically,for the complex $[PdClBr_2(SCN)]^{2-}$,the geometrical isomers are $cis$ and $trans$ with respect to the $Br$ ligands.Considering the linkage isomerism ($SCN$ vs $NCS$),the total number of isomers is $2 	imes 2 = 4$.

The number of isomers possible for the square planar complex $K_2[PdClBr_2(SCN)]$ is

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