(B) Potassium crystallizes in a $BCC$ system. Number of moles of potassium $= \frac{39 \ g}{39 \ g/mol} = 1 \ mol$. $1 \ mol$ of atoms contains $N$ at

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(B) Potassium crystallizes in a $BCC$ system. Number of moles of potassium $= \frac{39 \ g}{39 \ g/mol} = 1 \ mol$. $1 \ mol$ of atoms contains $N$ atoms. In a $BCC$ unit cell, the number of atoms per unit cell is $2$. Therefore, the number of unit cells $= \frac{\text{Total number of atoms}}{\text{Atoms per unit cell}} = \frac{N}{2}$.

Class 12 Chemistry Solid State Crystal structure and Coordination number

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The number of unit cells present in $39 \ g$ of potassium if it crystallizes as a body-centered cubic $(BCC)$ structure is ($N = \text{Avogadro number}$, $\text{At. wt. of potassium} = 39$).

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A
$\frac{N}{4}$
B
$\frac{N}{2}$
C
$\frac{N}{3}$
D
$N$

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The number of unit cells present in $39 \ g$ of potassium if it crystallizes as a body-centered cubic $(BCC)$ structure is ($N = \text{Avogadro number}$, $\text{At. wt. of potassium} = 39$).

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