The number of unpaired electrons is maximum i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electronic configurations of the given elements are:$Ti (Z=22): [Ar] 3d^2 4s^2$ (Unpaired electrons = $2$)$V (Z=23): [Ar] 3d^3 4s^2$ (Unpaired

Vedclass · Accepted Answer

$Cr$

Vedclass · Answer

(A) The electronic configurations of the given elements are:$Ti (Z=22): [Ar] 3d^2 4s^2$ (Unpaired electrons = $2$)$V (Z=23): [Ar] 3d^3 4s^2$ (Unpaired electrons = $3$)$Cr (Z=24): [Ar] 3d^5 4s^1$ (Unpaired electrons = $6$)$Fe (Z=26): [Ar] 3d^6 4s^2$ (Unpaired electrons = $4$)$Sc (Z=21): [Ar] 3d^1 4s^2$ (Unpaired electrons = $1$)Thus,$Cr$ has the maximum number of unpaired electrons.

column-$I$ $(\text{Property})$	column-$II$ $(\text{Metal})$
$i$. An element which can show $+8$ oxidation state	$a$. $Mn$
$ii$. $3d$ series element that can show upto $+7$ oxidation state	$b$. $Cr$
$iii$. $3d$ series element with highest melting point	$c$. $Os$

The number of unpaired electrons is maximum in (Atomic no. : $Ti = 22; V = 23; Cr = 24; Fe = 26$)

Similar Questions

Explain the variations in atomic radii of transition elements in a group.

Number of unpaired electrons in $Mn^{4+}$ is

Which of the following pairs of elements cannot form an alloy?

All $Zn(II)$ compounds are white because

Vedclass Test Series

Exam Paper Generator

Online Exam Module