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(B) In three-dimensional space,a molecule has a total of $3N$ degrees of freedom,where $N$ is the number of atoms. For a diatomic molecule,$N = 2$,so

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$1$

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(B) In three-dimensional space,a molecule has a total of $3N$ degrees of freedom,where $N$ is the number of atoms. For a diatomic molecule,$N = 2$,so the total degrees of freedom are $3 	imes 2 = 6$.These $6$ degrees of freedom are categorized as follows:$1$. Translational degrees of freedom: $3$ (along the $x, y,$ and $z$ axes).$2$. Rotational degrees of freedom: $2$ (for a linear diatomic molecule).$3$. Vibrational degrees of freedom: The remaining degrees of freedom are calculated as $6 - (3 + 2) = 1$.Therefore,a diatomic molecule has $1$ vibrational degree of freedom.

The number of vibrational degrees of freedom of a diatomic molecule is

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