The number of ways in which ten candidates $A_1, A_2, \dots, A_{10}$ can be ranked such that $A_1$ is always above $A_{10}$ is:

  • A
    $5!$
  • B
    $2(5!)$
  • C
    $10!$
  • D
    $\frac{1}{2}(10!)$

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