The odds in favour of getting a sum that is a multiple of $3$,when a pair of dice is thrown,is:

If $A$ and $B$ are arbitrary events,then

$A$,$B$,and $C$ are three events,one of which must and only one can happen. The odds in favor of $A$ are $4 : 6$,and the odds against $B$ are $7 : 3$. Thus,the odds against $C$ are:

Three critics review a book. For the three critics,the odds in favour of the book are $2:5$,$3:4$,and $4:3$ respectively. The probability that the majority is in favour of the book is given by

The three ships namely $A$,$B$ and $C$ sail from India to Africa. If the odds in favour of the ships reaching safely are $2:5$,$3:7$ and $6:11$ respectively,then the probability of all of them arriving safely is

Let $A$ and $B$ be two events such that $P(A) = 0.3$ and $P(A \cup B) = 0.8$. If $A$ and $B$ are independent events,then $P(B) = $