The three ships namely A,B and C sail from In | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The probability that ship $A$ reaches safely is $P(A) = \frac{2}{2+5} = \frac{2}{7}$.The probability that ship $B$ reaches safely is $P(B) = \frac

Vedclass · Accepted Answer

$\frac{18}{595}$

Vedclass · Answer

(A) The probability that ship $A$ reaches safely is $P(A) = \frac{2}{2+5} = \frac{2}{7}$.The probability that ship $B$ reaches safely is $P(B) = \frac{3}{3+7} = \frac{3}{10}$.The probability that ship $C$ reaches safely is $P(C) = \frac{6}{6+11} = \frac{6}{17}$.Since the events are independent,the probability that all of them arrive safely is $P(A \cap B \cap C) = P(A) 	imes P(B) 	imes P(C)$.$P(A \cap B \cap C) = \frac{2}{7} 	imes \frac{3}{10} 	imes \frac{6}{17} = \frac{36}{1190} = \frac{18}{595}$.

The three ships namely $A$,$B$ and $C$ sail from India to Africa. If the odds in favour of the ships reaching safely are $2:5$,$3:7$ and $6:11$ respectively,then the probability of all of them arriving safely is

Similar Questions

For two events $A$ and $B$,$P(A)=0.5$,$P(A \cup B)=0.6$ and $P(B)=K$ are given. If $A$ and $B$ are independent events,then $K=$ . . . . . . .

For an event,the odds against are $6 : 5$. The probability that the event does not occur is

If a number is selected from the first $30$ natural numbers, then the probability that the number selected is divisible by $4$ or $7$ is:

Three critics review a book. For the three critics,the odds in favour of the book are $2:5$,$3:4$,and $4:3$ respectively. The probability that the majority is in favour of the book is given by

$A$ and $B$ are two events such that $P(A)=0.54$,$P(B)=0.69$ and $P(A \cap B)=0.35$. Find $P(A' \cap B')$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module