The only elastic modulus that applies to fluids is

$A$ ball is taken to a depth of $200 \ m$ in a lake. The decrease in its volume is $0.1\%$. Calculate the bulk modulus of the material of the ball.

$A$ solid copper cube of $7 \,cm$ edge is subjected to a hydraulic pressure of $8000 \,kPa$. The volume contraction of the copper cube is (Bulk modulus of copper $= 140 \,GPa$)

When a rubber ball is taken to a depth of $h$ meters in deep sea,its volume decreases by $0.5\, \%$. Calculate the depth $h$. (Given: Bulk modulus of rubber $B = 9.8 \times 10^{8} \, \text{N/m}^2$,Density of sea water $\rho = 10^{3} \, \text{kg/m}^3$,$g = 9.8 \, \text{m/s}^2$)

The average depth of the Indian Ocean is about $3000 \,m$. The value of fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at the bottom of the ocean is (given that the bulk modulus of water is $2.2 \times 10^9 \,N/m^2$,$g = 9.8 \,m/s^2$,$\rho_{H_2O} = 1000 \,kg/m^3$):

If the average depth of an ocean is $4000 \ m$ and the bulk modulus of water is $2 \times 10^9 \ N m^{-2}$,then the fractional compression $\frac{\Delta V}{V}$ of water at the bottom of the ocean is $\alpha \times 10^{-2}$. The value of $\alpha$ is . . . . . . (Given,$g=10 \ m s^{-2}, \rho=1000 \ kg m^{-3}$)