The optical rotation of the alpha-form of a p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the fraction of the $\alpha$-form be $X$ and the fraction of the $\beta$-form be $(1 - X)$.The equilibrium rotation is given by the weighted a

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) Let the fraction of the $\alpha$-form be $X$ and the fraction of the $\beta$-form be $(1 - X)$.The equilibrium rotation is given by the weighted average: $150.7(X) + 52.8(1 - X) = 80.2$.Expanding the equation: $150.7X + 52.8 - 52.8X = 80.2$.Simplifying the terms: $97.9X = 80.2 - 52.8$.$97.9X = 27.4$.$X = \frac{27.4}{97.9} \approx 0.2799$.Converting to percentage: $0.2799 	imes 100 \approx 28 \%$.Thus,the percentage of the $\alpha$-form is $28 \%$.

The optical rotation of the $\alpha$-form of a pyranose is $+150.7^{\circ}$,that of the $\beta$-form is $+52.8^{\circ}$. In solution,an equilibrium mixture of these anomers has an optical rotation of $+80.2^{\circ}$. The percentage of the $\alpha$-form in the equilibrium mixture is $....... \%$.

Similar Questions

Write a note on the structure of fructose.

Which reagent/s can be used to distinguish glucose and fructose?
$I$. Bromine water
$II$. Tollen's reagent
$III$. Schiff's reagent

What is the phenomenon of rapid interconversion of $\alpha-D-$glucose into $\beta-D-$glucose in solution called?

How do you explain the absence of aldehyde group in the pentaacetate of $D$-glucose?

$A$ polysaccharide '$X$' on boiling with dil $H_2SO_4$ at $393 \ K$ under $2-3 \ atm$ pressure yields '$Y$'. '$Y$' on treatment with bromine water gives gluconic acid. '$X$' contains $\beta-$glycosidic linkages only. Compound '$X$' is ..... .

Vedclass Test Series

Exam Paper Generator

Online Exam Module