The orbital angular momentum of a $p-$ electron is given as

  • A
    $\frac{h}{\sqrt{2} \pi}$
  • B
    $\sqrt{3} \frac{h}{2 \pi}$
  • C
    $\sqrt{\frac{3}{2}} \frac{h}{\pi}$
  • D
    $\sqrt{6} \frac{h}{2 \pi}$

Explore More

Similar Questions

The total number of electrons that can be accommodated in all the orbitals having principal quantum number $n = 2$ and azimuthal quantum number $l = 1$ is

The orbital angular momentum of an electron in an orbital is given by $\sqrt{l(l + 1)} \cdot \frac{h}{2\pi}$. For an $s$-electron,this momentum is:

For the electronic configuration $1s^2 2s^2 2p^3$,what is the number of electrons having $n = 2, l = 1$,and $s = +1/2$?

The atomic number of an element is $35$ and its mass number is $81$. The number of electrons in the outermost shell is:

The relation between $n_m$ (the number of permissible values of magnetic quantum number $m$) for a given value of azimuthal quantum number $l$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo