The order and the degree of the differential | vedclass

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(A) The given differential equation is $\left( \frac{d^2s}{dt^2} \right)^2 + 3\left( \frac{ds}{dt} \right)^3 + 4 = 0$. The order of a differential equ

Vedclass · Accepted Answer

$2, 2$

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(A) The given differential equation is $\left( \frac{d^2s}{dt^2} \right)^2 + 3\left( \frac{ds}{dt} \right)^3 + 4 = 0$. The order of a differential equation is the highest order derivative present in the equation. Here,the highest order derivative is $\frac{d^2s}{dt^2}$,so the order is $2$. The degree of a differential equation is the power of the highest order derivative when the equation is expressed as a polynomial in derivatives. Here,the power of $\frac{d^2s}{dt^2}$ is $2$. Therefore,the order is $2$ and the degree is $2$.

The order and the degree of the differential equation $\left( \frac{d^2s}{dt^2} \right)^2 + 3\left( \frac{ds}{dt} \right)^3 + 4 = 0$ are

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