The order of a reaction with rate equals $k[C_A]^{3/2} [C_B]^{-1/2}$ is

  • A
    $2$
  • B
    $1$
  • C
    $-\frac{1}{2}$
  • D
    $\frac{3}{2}$

Explore More

Similar Questions

The reaction $2N_2O_5 \rightleftharpoons 2N_2O_4 + O_2$ is

$A$ reaction is first order with respect to a reactant $A$ and second order with respect to reactant $B$. What is the effect on the rate when the concentration of both $A$ and $B$ is doubled?

$A$ study of chemical kinetics of the reaction $A + B \to$ Products,gave the following data at $25 \ ^oC$.
$Exp. \ No.$ $[A]$ $[B]$ $Rate$
$1.$ $1.0$ $0.15$ $4.2 \times 10^{-6}$
$2.$ $2.0$ $0.15$ $8.4 \times 10^{-6}$
$3.$ $1.0$ $0.20$ $5.6 \times 10^{-6}$

Find out the rate law.

The reaction $CH_{3}COF + H_{2}O \rightleftharpoons CH_{3}COOH + HF$ is studied under two conditions:
Condition $I$: $[H_{2}O]_{0} = 1.00 \ M$,$[CH_{3}COF]_{0} = 0.01 \ M$
Condition $II$: $[H_{2}O]_{0} = 0.02 \ M$,$[CH_{3}COF]_{0} = 0.80 \ M$
Time $(t)$ min (Condition $I$) / $[CH_{3}COF]$ $M$ Time $(t)$ min (Condition $II$) / $[H_{2}O]$ $M$
$0$ / $0.01000$ $0$ / $0.0200$
$10$ / $0.00867$ $10$ / $0.0176$
$20$ / $0.00735$ $20$ / $0.0156$
$40$ / $0.00540$ $40$ / $0.0122$

Determine the overall order of the reaction and calculate the rate constant.

The rate constant for a second order reaction,$A \rightarrow \text{Product}$ is $1.62 \ M^{-1} \ s^{-1}$. What will be the rate of reaction when concentration of reactant is $2 \times 10^{-3} \ M$ (in $M \ s^{-1}$)?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo