The order of the average bond length of the g | vedclass

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(B) The bond length depends on the bond order (multiplicity) and the atomic radii of the bonded atoms.Bond length is inversely proportional to bond or

Vedclass · Accepted Answer

$C \equiv C < C=O < C=N < N-O$

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(B) The bond length depends on the bond order (multiplicity) and the atomic radii of the bonded atoms.Bond length is inversely proportional to bond order: $Triple \ bond Comparing the given bonds:$1. C \equiv C$ (Bond order $3$)$2. C=O$ (Bond order $2$)$3. C=N$ (Bond order $2$)$4. N-O$ (Bond order $1$)Since $C=O$ has a higher bond polarity and smaller atomic radii compared to $C=N$,the $C=O$ bond is shorter than $C=N$.Thus,the order of bond length is $C \equiv C < C=O < C=N < N-O$.

The order of the average bond length of the given bonds is

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