The output Y of the given network is :- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given circuit consists of a $NOR$ gate,a $NOT$ gate (implemented by a $NAND$ gate with shorted inputs),and an $AND$ gate.$1$. The output of th

Vedclass · Accepted Answer

$B$

Vedclass · Answer

(C) The given circuit consists of a $NOR$ gate,a $NOT$ gate (implemented by a $NAND$ gate with shorted inputs),and an $AND$ gate.$1$. The output of the $NOR$ gate with inputs $A$ and $B$ is $\overline{A+B}$.$2$. This output is fed into a $NAND$ gate whose inputs are shorted,acting as a $NOT$ gate. Thus,the output becomes $\overline{\overline{A+B}} = A+B$.$3$. This signal $(A+B)$ and the input $B$ are fed into an $AND$ gate.$4$. Therefore,the final output $Y = (A+B) \cdot B$.$5$. Using Boolean algebra: $Y = A \cdot B + B \cdot B = A \cdot B + B = B(A+1) = B \cdot 1 = B$.

The output $Y$ of the given network is :-

Similar Questions

What logic gate is formed by the combination of gates shown below?

In the Boolean algebra,$(\overline {\bar A \cdot \bar B} ) \cdot A$ is equal to:

Assertion : $NAND$ or $NOR$ gates are called digital building blocks.
Reason : The repeated use of $NAND$ (or $NOR$) gates can produce all the basic or complicated gates.

The logic circuit shown below is equivalent to which of the following?

Which logic gate is represented by the following diagram?

Vedclass Test Series

Exam Paper Generator

Online Exam Module