The output of a step-down transformer is measured to be $24 \ V$,when connected to a $12 \ W$ light bulb. The value of peak current is $...... \ A$. (in $A$)

$100\text{ W}$ रेटेड एक प्रकाश बल्ब $220\text{ V}$, $50\text{ Hz}$ के $AC$ स्रोत से जुड़ा है। बल्ब से प्रवाहित होने वाली $rms$ धारा है: (in $text{ A}$)

The $r.m.s.$ value of the given current $I = I_0 + I_1 \sin \omega t$ is

The ratio of the peak value to the root mean square (r.m.s.) value of an alternating current is:

Match the following:
Currents $r.m.s.$ values
$(1) x_0 \sin \omega t$ $(i) x_0$
$(2) x_0 \sin \omega t \cos \omega t$ $(ii) \frac{x_0}{\sqrt{2}}$
$(3) x_0 \sin \omega t + x_0 \cos \omega t$ $(iii) \frac{x_0}{2\sqrt{2}}$

The rms value of the potential difference $v$ shown in the figure is