The ratio of the peak value to the root mean square (r.m.s.) value of an alternating current is:

  • A
    $1$
  • B
    $1/2$
  • C
    $\sqrt{2}$
  • D
    $1/\sqrt{2}$

Explore More

Similar Questions

An electric current has both $DC$ and $AC$ components. The $DC$ component is $8 \ A$ and the $AC$ component is given as $I = 6 \sin \omega t$. The $rms$ value of the resultant current is . . . . . . (in $A$)

The $r.m.s.$ voltage of the waveform shown is:

The output voltage of a step-down transformer is measured to be $24 \text{ V}$, when connected to a $12 \text{ W}$ light bulb. The value of the peak current is . . . . . . .

One complete set of negative and positive values of alternating quantities is called

An alternating current is given by $I = I_A \sin \omega t + I_B \cos \omega t$. The r.m.s. current will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo