(D) The oxidation number of $H$ is $+1$ and $O$ is $-2$. Let the oxidation number of $S$ be $x$. For the molecule $H_2SO_4$,the sum of oxidation numbe

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(D) The oxidation number of $H$ is $+1$ and $O$ is $-2$. Let the oxidation number of $S$ be $x$. For the molecule $H_2SO_4$,the sum of oxidation numbers is $0$. $2(+1) + x + 4(-2) = 0$ $2 + x - 8 = 0$ $x - 6 = 0$ $x = +6$ Therefore,the oxidation number of sulphur in $H_2SO_4$ is $+6$.