(D) To find the oxidation number of iodine $(I)$ in each compound:$1$. In $KIO_3$: $1 + x + 3(-2) = 0 \implies x = +5$$2$. In $KI$: $1 + x = 0 \implie

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(D) To find the oxidation number of iodine $(I)$ in each compound:$1$. In $KIO_3$: $1 + x + 3(-2) = 0 \implies x = +5$$2$. In $KI$: $1 + x = 0 \implies x = -1$$3$. In $IF_5$: $x + 5(-1) = 0 \implies x = +5$$4$. In $KIO_4$: $1 + x + 4(-2) = 0 \implies x = +7$Comparing the values: $+5, -1, +5, +7$. The highest oxidation number is $+7$ in $KIO_4$.