The oxidation state (n), coordination number | vedclass

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(B) The structure of $Al_2Cl_6$ is a dimer where each $Al$ atom is bonded to $4$ chlorine atoms (two terminal and two bridging).$(I)$ Oxidation state

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$3, 4, 8$

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(B) The structure of $Al_2Cl_6$ is a dimer where each $Al$ atom is bonded to $4$ chlorine atoms (two terminal and two bridging).$(I)$ Oxidation state $(n)$ of $Al$ in $Al_2Cl_6$: $2x + 6(-1) = 0 \implies 2x = 6 \implies x = +3$.$(II)$ Coordination number $(CN)$ of $Al$: Each $Al$ atom is surrounded by $4$ chlorine atoms, so $CN = 4$.$(III)$ Number of valence electrons $(N)$ around $Al$: Since each $Al$ atom is bonded to $4$ chlorine atoms by covalent bonds (including coordinate bonds), it shares $4$ electron pairs, resulting in $4 	imes 2 = 8$ valence electrons around each $Al$ atom.Therefore, the values are $3, 4, 8$. The correct option is $(B)$.

The oxidation state $(n)$, coordination number $(CN)$ of $Al$, and the number of valence electrons around $Al$ $(N)$ in $Al_2Cl_6$ are respectively:

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