The pair of compounds which cannot exist toge | vedclass

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(D) Compounds that react with each other cannot coexist in an aqueous solution.$I.$ $NaH_2PO_4$ (acidic salt) and $NaHCO_3$ (amphoteric salt) can coex

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only $IV$

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(D) Compounds that react with each other cannot coexist in an aqueous solution.$I.$ $NaH_2PO_4$ (acidic salt) and $NaHCO_3$ (amphoteric salt) can coexist as they do not react significantly.$II.$ $Na_2CO_3$ and $NaHCO_3$ are both salts of a weak acid and strong base and can coexist.$III.$ $NaOH$ (strong base) and $NaH_2PO_2$ (salt of hypophosphorous acid) can coexist as $NaH_2PO_2$ is not acidic enough to react with $NaOH$.$IV.$ $NaHCO_3$ (acidic salt) and $NaOH$ (strong base) react to form $Na_2CO_3$ and $H_2O$:$NaHCO_3 + NaOH \rightarrow Na_2CO_3 + H_2O$Therefore,only the pair in $IV$ cannot exist together.

List-$I$ (Acid)	List-$II$ $(K_a)$
$A$. Phenol	$I$. $1 \times 10^{-13}$
$B$. Benzoic acid	$II$. $3.0 \times 10^{-8}$
$C$. $HClO$	$III$. $1.0 \times 10^{-10}$
$D$. $CH_3COOH$	$IV$. $6.5 \times 10^{-5}$
	$V$. $1.75 \times 10^{-5}$

The pair of compounds which cannot exist together in aqueous solution is:
$I.$ $NaH_2PO_4$ and $NaHCO_3$
$II.$ $Na_2CO_3$ and $NaHCO_3$
$III.$ $NaOH$ and $NaH_2PO_2$
$IV.$ $NaHCO_3$ and $NaOH$

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The pair of compounds which cannot exist together in aqueous solution is:$I.$ $NaH_2PO_4$ and $NaHCO_3$$II.$ $Na_2CO_3$ and $NaHCO_3$$III.$ $NaOH$ and $NaH_2PO_2$$IV.$ $NaHCO_3$ and $NaOH$