The pair of species with similar shape is

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(A) To determine the shape of the species,we use the $VSEPR$ theory based on the number of bonding pairs and lone pairs of electrons.$1$. $PCl_3$ has

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$PCl_3, NH_3$

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(A) To determine the shape of the species,we use the $VSEPR$ theory based on the number of bonding pairs and lone pairs of electrons.$1$. $PCl_3$ has $3$ bond pairs and $1$ lone pair on $P$,resulting in a trigonal pyramidal shape. $NH_3$ also has $3$ bond pairs and $1$ lone pair on $N$,resulting in a trigonal pyramidal shape. Thus,they have similar shapes.$2$. $CF_4$ is tetrahedral ($4$ bond pairs,$0$ lone pairs),while $SF_4$ is see-saw shaped ($4$ bond pairs,$1$ lone pair).$3$. $PbCl_2$ is bent (angular) due to the presence of a lone pair on $Pb$,while $CO_2$ is linear.$4$. $PF_5$ is trigonal bipyramidal,while $IF_5$ is square pyramidal.Therefore,the correct pair is $PCl_3$ and $NH_3$.

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