The perimeter of a triangle with vertices (0, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the perimeter of a triangle,we calculate the sum of the lengths of all its sides. Let the vertices of the triangle be $A(0,4)$,$O(0,0)$,an

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) To find the perimeter of a triangle,we calculate the sum of the lengths of all its sides. Let the vertices of the triangle be $A(0,4)$,$O(0,0)$,and $B(3,0)$.The perimeter of $	riangle AOB = 	ext{Sum of the lengths of all its sides} = d(AO) + d(OB) + d(AB)$.The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.$1$. Distance $d(AO) = \sqrt{(0-0)^2 + (0-4)^2} = \sqrt{0 + 16} = 4$.$2$. Distance $d(OB) = \sqrt{(3-0)^2 + (0-0)^2} = \sqrt{9 + 0} = 3$.$3$. Distance $d(AB) = \sqrt{(3-0)^2 + (0-4)^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5$.Perimeter $= 4 + 3 + 5 = 12$.Thus,the required perimeter of the triangle is $12$.

The perimeter of a triangle with vertices $(0,4), (0,0)$ and $(3,0)$ is

Similar Questions

Show that $A(1, 4)$,$B(7, -2)$,and $C(9, 6)$ are the vertices of an isosceles triangle.

In which ratio does the point $P (-4, 3)$ divide the line segment joining the points $A (1, -2)$ and $B (-6, 5)$?

The fourth vertex $D$ of a parallelogram $ABCD$ whose three vertices are $A(-2,3)$,$B(6,7)$,and $C(8,3)$ is

The line segment joining the points $A(3, 2)$ and $B(5, 1)$ is divided at the point $P$ in the ratio $1: 2$,and it lies on the line $3x - 18y + k = 0$. Find the value of $k$.

State whether the following statement is true or false. Justify your answer.
Point $P (0, -7)$ is the point of intersection of the $y$-axis and the perpendicular bisector of the line segment joining the points $A (-1, 0)$ and $B (7, -6)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module