The perimeter of an equilateral triangle is $18$. Then,the length of its altitude is $\ldots \ldots \ldots$

  • A
    $6$
  • B
    $3$
  • C
    $6 \sqrt{3}$
  • D
    $3 \sqrt{3}$

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Similar Questions

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In $\Delta ABC$,$m \angle A = 90^{\circ}$ and $\overline{AD}$ is an altitude to the hypotenuse $BC$. Then,$AD^{2} = \ldots$

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