The period of the function f(theta) = sin fra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The period of $\sin(a	heta)$ is given by $\frac{2\pi}{|a|}$.For the first term $\sin(\frac{	heta}{3})$,the period $T_1 = \frac{2\pi}{1/3} = 6\pi

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(D) The period of $\sin(a	heta)$ is given by $\frac{2\pi}{|a|}$.For the first term $\sin(\frac{	heta}{3})$,the period $T_1 = \frac{2\pi}{1/3} = 6\pi$.For the second term $\cos(\frac{	heta}{2})$,the period $T_2 = \frac{2\pi}{1/2} = 4\pi$.The period of the sum of two periodic functions is the $L.C.M.$ of their individual periods.$L.C.M.$ of $6\pi$ and $4\pi$ is $12\pi$.Therefore,the period of $f(	heta)$ is $12\pi$.

The period of the function $f(\theta) = \sin \frac{\theta}{3} + \cos \frac{\theta}{2}$ is (in $\pi$)

Similar Questions

$\int_0^2 \frac{2x-2}{2x-x^2} dx$ is equal to

Which one of the following statements is incorrect about menstruation?

If $\sqrt{\frac{y}{x}}+\sqrt{\frac{x}{y}}=2$,then $\frac{d y}{d x}$ is equal to

If $\omega$ is a complex cube root of unity,then $(x+1)(x+\omega)(x-\omega-1)$ is equal to

The value of $\lambda$ such that $\lambda x^2-10 x y+12 y^2+5 x-16 y-3=0$ represents a pair of straight lines is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module