(B) Area of the house on the slide,$A_o = 1.75 \; cm^2$.Area of the image of the house on the screen,$A_i = 1.55 \; m^2$.Convert the area of the image

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(B) Area of the house on the slide,$A_o = 1.75 \; cm^2$.Area of the image of the house on the screen,$A_i = 1.55 \; m^2$.Convert the area of the image to $cm^2$: $A_i = 1.55 \times (100 \; cm)^2 = 1.55 \times 10^4 \; cm^2$.The areal magnification $m_a$ is defined as the ratio of the area of the image to the area of the object: $m_a = \frac{A_i}{A_o} = \frac{1.55 \times 10^4}{1.75}$.$m_a = 8857.14$.The linear magnification $m_l$ is the square root of the areal magnification: $m_l = \sqrt{m_a} = \sqrt{8857.14} \approx 94.11$.

Class 12 Physics Ray Optics and Optical Instruments Mix Examples-Ray Optics

Medium

The photograph of a house occupies an area of $1.75 \; cm^2$ on a $35 \; mm$ slide. The slide is projected onto a screen,and the area of the house on the screen is $1.55 \; m^2$. What is the linear magnification of the projector-screen arrangement?

A
$11.45$
B
$94.11$
C
$52.36$
D
$78.36$

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Ray Optics and Optical Instruments

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Mix Examples-Ray Optics

To find the focal length of a convex mirror,a student records the following data:

Object Pin Convex Lens Convex Mirror Image Pin

$22.2 \, cm$ $32.2 \, cm$ $45.8 \, cm$ $71.2 \, cm$

The focal length of the convex lens is $f_1$ and that of the mirror is $f_2$. Taking index correction to be negligibly small,$f_1$ and $f_2$ are close to:

Object Pin	Convex Lens	Convex Mirror	Image Pin
$22.2 \, cm$	$32.2 \, cm$	$45.8 \, cm$	$71.2 \, cm$

DifficultJEE MAIN 2016

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What is rectilinear propagation of light? Explain ray of light and beam of light.

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EasyIIT 1996

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The photograph of a house occupies an area of $1.75 \; cm^2$ on a $35 \; mm$ slide. The slide is projected onto a screen,and the area of the house on the screen is $1.55 \; m^2$. What is the linear magnification of the projector-screen arrangement?

Similar Questions

$A$ prism with a refractive index of $1.5$ and an angle $A = 4^o$ is placed in front of a mirror. When the incident ray is reflected by the mirror,what is the total deviation in degrees?

$A$ small source of light is to be suspended directly above the centre of a circular table of radius $R$. What should be the height of the light source above the table so that the intensity of light is maximum at the edges of the table compared to any other height of the source?

What is rectilinear propagation of light? Explain ray of light and beam of light.

Which of the following form$(s)$ a virtual and erect image for all positions of the object?

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