The points of maximum and minimum attraction | vedclass

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(D) The force between the atoms is given by $F = -\frac{dU}{dr}$.Attraction force is negative,so $F = -\frac{dU}{dr}

Vedclass · Accepted Answer

$S$ and $T$

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(D) The force between the atoms is given by $F = -\frac{dU}{dr}$.Attraction force is negative,so $F = -\frac{dU}{dr}  0$. The magnitude of the attractive force is $|F| = |\frac{dU}{dr}|$,which represents the slope of the $U-r$ curve.At point $S$,the slope of the curve is positive and reaches its maximum value. Thus,the attraction is maximum at point $S$.At point $T$,the curve becomes horizontal,meaning the slope $\frac{dU}{dr} = 0$. Thus,the attraction force is minimum (zero) at point $T$.Therefore,the points of maximum and minimum attraction are $S$ and $T$ respectively.

Column-$I$	Column-$II$
$(1)$ Conservative force	$(a)$ Frictional force
$(2)$ Non-conservative force	$(b)$ Gravitational force
	$(c)$ Internal force

The points of maximum and minimum attraction in the curve between potential energy $(U)$ and distance $(r)$ of a diatomic molecule are respectively:

Similar Questions

Match Column-$I$ with Column-$II$.

Column-$I$ Column-$II$

$(1)$ Conservative force $(a)$ Frictional force

$(2)$ Non-conservative force $(b)$ Gravitational force

$(c)$ Internal force

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For a system of conservative forces,the potential energy $U$ is given by the formula $U = ax^2 - bx$,where $a$ and $b$ are constants. Determine the force $F$.

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Reason $(R) :-$ All conservative forces are central forces.

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