The polarising angle for a transparent medium | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Brewster's Law,the refractive index $\mu$ of a medium is related to the polarising angle $	heta$ by the equation $\mu = 	an 	heta$

Vedclass · Accepted Answer

$	heta=\cot ^{-1}\left(\frac{v}{c}ight)$

Vedclass · Answer

(B) According to Brewster's Law,the refractive index $\mu$ of a medium is related to the polarising angle $	heta$ by the equation $\mu = 	an 	heta$. By definition,the refractive index $\mu$ is the ratio of the speed of light in air $(c)$ to the speed of light in the medium $(v)$,so $\mu = \frac{c}{v}$. Equating the two expressions for $\mu$,we get $	an 	heta = \frac{c}{v}$. Taking the reciprocal of both sides,we have $\cot 	heta = \frac{1}{	an 	heta} = \frac{v}{c}$. Therefore,the relation is $	heta = \cot ^{-1}\left(\frac{v}{c}ight)$.

The polarising angle for a transparent medium is $\theta$,and $v$ is the speed of light in that medium. Then the relation between $\theta$ and $v$ is (where $c$ is the velocity of light in air).

Similar Questions

Light is incident at an angle $i$ on a glass slab. The reflected ray is completely polarised. The angle of refraction is

The angle of polarisation for any medium is $60^{\circ}$. What will be the critical angle for this medium?

For a given medium, the polarizing angle is $60^o$. What will be the critical angle for this medium?

The polarising angle for water is $53^\circ 4'$. If light is incident at this angle on the surface of water and reflected, the angle of refraction is:

Let the speed of light in a medium be $V$ and the polarising angle be $i_p$. If $C$ is the speed of light in vacuum,what is the relation between them?

Vedclass Test Series

Exam Paper Generator

Online Exam Module