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(C) The instantaneous velocity is given by $v = \frac{\Delta x}{\Delta t}$.Using the data from the table:For the interval $t = 0$ to $t = 1 \ s$: $v_1

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Non-uniform,accelerated

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(C) The instantaneous velocity is given by $v = \frac{\Delta x}{\Delta t}$.Using the data from the table:For the interval $t = 0$ to $t = 1 \ s$: $v_1 = \frac{0 - (-2)}{1} = 2 \ m/s$.For the interval $t = 1$ to $t = 2 \ s$: $v_2 = \frac{6 - 0}{1} = 6 \ m/s$.For the interval $t = 2$ to $t = 3 \ s$: $v_3 = \frac{16 - 6}{1} = 10 \ m/s$.Since the velocity is changing with time $(2 \ m/s, 6 \ m/s, 10 \ m/s)$,the motion is non-uniform.Since the velocity is increasing,the motion is accelerated. Thus,the motion is non-uniform and accelerated.

$t (s)$	$0$	$1$	$2$	$3$
$x (m)$	$-2$	$0$	$6$	$16$

Column $I$	Column $II$
$(A)$ Velocity-time graph	$(p)$ Slope $\rightarrow$ negative
$(B)$ Acceleration-time graph	$(q)$ Slope $\rightarrow$ positive
$(C)$ Displacement-time graph	$(r)$ Slope $\rightarrow$ zero
	$(s)$ $\|\text{Slope}\| \rightarrow$ increasing
	$(t)$ $\|\text{Slope}\| \rightarrow$ decreasing
	$(u)$ $\|\text{Slope}\| \rightarrow$ constant

The position of a particle moving along the $X-$axis at certain times is given below. Which of the following describes the motion correctly?
$t (s)$ $0$ $1$ $2$ $3$
$x (m)$ $-2$ $0$ $6$ $16$

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The position of a particle moving along the $X-$axis at certain times is given below. Which of the following describes the motion correctly?$t (s)$$0$$1$$2$$3$$x (m)$$-2$$0$$6$$16$