The position of a particle moving in the $xy$-plane at any time $t$ is given by $x = (3t^2 - 6t) \text{ m}$ and $y = (t^2 - 2t) \text{ m}$. Select the correct statement about the moving particle from the following:
- AThe acceleration of the particle is zero at $t = 0 \text{ s}$.
- BThe velocity of the particle is zero at $t = 0 \text{ s}$.
- CThe velocity of the particle is zero at $t = 1 \text{ s}$.
- DThe velocity and acceleration of the particle are never zero.
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View Solution$A$ particle initially at the origin starts moving in the $xy$-plane with a velocity component $\vec{V} = (6 + 2t) \hat{i} + (4 + 2\sqrt{3}t) \hat{j} \text{ m/s}$. The acceleration of the particle in $\text{m/s}^2$ is ($x, y$ are measured in meters, $t$ in seconds, respectively).
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