The potential at point E for the given figure | vedclass

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(D) Let the potential at point $E$ be $V_E$. The point $C$ is grounded,so its potential $V_C = 0 \ V$. Since $A, B, C$ are connected by ideal wires,$V

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(D) Let the potential at point $E$ be $V_E$. The point $C$ is grounded,so its potential $V_C = 0 \ V$. Since $A, B, C$ are connected by ideal wires,$V_A = V_B = V_C = 0 \ V$.Applying Kirchhoff's Current Law $(KCL)$ at node $E$:Sum of currents leaving node $E$ is zero.$\frac{V_E - 10 - 0}{1} + \frac{V_E - 30 - 0}{2} + \frac{V_E - (-50) - 0}{2} = 0$Multiplying the entire equation by $2$:$2(V_E - 10) + (V_E - 30) + (V_E + 50) = 0$$2V_E - 20 + V_E - 30 + V_E + 50 = 0$$4V_E = 0$$V_E = 0 \ V$

The potential at point $E$ for the given figure is ................ $V$.

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