The resistance of each arm of the Wheatstone bridge is $10 \, \Omega$. A resistance of $10 \, \Omega$ is connected in series with a galvanometer. Then, the equivalent resistance across the battery will be:

  • A
    $15 \, \Omega$
  • B
    $20 \, \Omega$
  • C
    $10 \, \Omega$
  • D
    $40 \, \Omega$

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