The potential at the point B in the given fig | vedclass

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(C) Let the potential at point $B$ be $V$.Since the capacitors $C_1 = 2 \ \mu F$ and $C_2 = 3 \ \mu F$ are in series,the charge $Q$ on both capacitors

Vedclass · Accepted Answer

$22$

Vedclass · Answer

(C) Let the potential at point $B$ be $V$.Since the capacitors $C_1 = 2 \ \mu F$ and $C_2 = 3 \ \mu F$ are in series,the charge $Q$ on both capacitors is the same.The potential difference across $C_1$ is $V_A - V_B = 40 - V$.Thus,$Q = C_1(V_A - V_B) = 2(40 - V)$.The potential difference across $C_2$ is $V_B - V_C = V - 10$.Thus,$Q = C_2(V_B - V_C) = 3(V - 10)$.Since the charges are equal:$2(40 - V) = 3(V - 10)$$80 - 2V = 3V - 30$$5V = 110$$V = 22 \ V$.

The potential at the point $B$ in the given figure is . . . . . . $V$.

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