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(D) Let the electromotive force of the cell be $E$ and its internal resistance be $r$. The current flowing through the circuit is $I = 2 \ A$.When the

Vedclass · Accepted Answer

$2.5$

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(D) Let the electromotive force of the cell be $E$ and its internal resistance be $r$. The current flowing through the circuit is $I = 2 \ A$.When the current flows in the normal direction,the terminal potential difference is given by $V_1 = E - Ir$.Substituting the given values: $20 = E - 2r$  --- (Equation $1$).When the direction of the current is reversed,the cell is being charged,so the terminal potential difference is given by $V_2 = E + Ir$.Substituting the given values: $30 = E + 2r$  --- (Equation $2$).Subtracting Equation $1$ from Equation $2$: $(E + 2r) - (E - 2r) = 30 - 20$.$4r = 10$.$r = 2.5 \ \Omega$.Thus,the internal resistance of the cell is $2.5 \ \Omega$.

Similar Questions

$10$ cells,each of $emf$ $E$ and internal resistance $r$,are connected in series to a variable external resistance. The figure shows the variation of the terminal potential difference of their combination with the current drawn from the combination. The $emf$ of each cell is ................ $V$.

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