The probability of the month of December in a | vedclass

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(A) The month of December has $31$ days.$31$ days consist of $4$ full weeks and $3$ extra days $(31 = 7 	imes 4 + 3)$.The $3$ extra days can be any o

Vedclass · Accepted Answer

$\frac{3}{7}$

Vedclass · Answer

(A) The month of December has $31$ days.$31$ days consist of $4$ full weeks and $3$ extra days $(31 = 7 	imes 4 + 3)$.The $3$ extra days can be any of the following combinations: (Sunday,Monday,Tuesday),(Monday,Tuesday,Wednesday),(Tuesday,Wednesday,Thursday),(Wednesday,Thursday,Friday),(Thursday,Friday,Saturday),(Friday,Saturday,Sunday),or (Saturday,Sunday,Monday).Out of these $7$ possible outcomes,the combinations containing a Saturday are: (Thursday,Friday,Saturday),(Friday,Saturday,Sunday),and (Saturday,Sunday,Monday).There are $3$ favorable outcomes out of $7$ total possibilities.Therefore,the probability is $\frac{3}{7}$.

The probability of the month of December in any year having $5$ Saturdays is $\ldots \ldots \ldots$

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