The product Z of the following reaction isCH_ | vedclass

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(C) The reaction of propyne $(CH_3-C \equiv CH)$ with $2$ equivalents of $HBr$ proceeds via Markovnikov's addition.In the first step,$HBr$ adds to the

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$CH_3-CBr_2-CH_3$

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(C) The reaction of propyne $(CH_3-C \equiv CH)$ with $2$ equivalents of $HBr$ proceeds via Markovnikov's addition.In the first step,$HBr$ adds to the triple bond to form $CH_3-CBr=CH_2$ ($2$-bromopropene).In the second step,another molecule of $HBr$ adds to the double bond following Markovnikov's rule,where the hydrogen atom attaches to the carbon with more hydrogens,resulting in the geminal dihalide $CH_3-CBr_2-CH_3$ ($2$,$2$-dibromopropane).

The product $Z$ of the following reaction is
$CH_3-C \equiv CH \xrightarrow{2 HBr} Z$

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The product $Z$ of the following reaction is$CH_3-C \equiv CH \xrightarrow{2 HBr} Z$