The product P in the following reaction is:Ph | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction is a variation of the Perkin condensation.In this reaction, an aromatic aldehyde $(PhCHO)$ reacts with an acid anhydride $((CH_

Vedclass · Accepted Answer

$Ph-CH=C(CH_3)-COOH$

Vedclass · Answer

(A) The given reaction is a variation of the Perkin condensation.In this reaction, an aromatic aldehyde $(PhCHO)$ reacts with an acid anhydride $((CH_3CH_2CO)_2O)$ in the presence of the sodium salt of the corresponding acid $(CH_3CH_2COONa)$.The $\alpha$-hydrogen of the anhydride is abstracted by the base to form a carbanion, which then attacks the carbonyl carbon of the aldehyde.Following dehydration and hydrolysis, the final product is an $\alpha,\beta$-unsaturated carboxylic acid.For the reactants $PhCHO$ and propionic anhydride $((CH_3CH_2CO)_2O)$, the product formed is $Ph-CH=C(CH_3)-COOH$ ($2$-methyl$-3-$phenylprop$-2-$enoic acid).

The product $P$ in the following reaction is:
$PhCHO + (CH_3CH_2CO)_2O \xrightarrow{CH_3CH_2COONa \text{ (anhydrous)}} P$

Similar Questions

The correct order of acidic strength is:

Which of the following is most reactive for nucleophilic substitution reaction?

The highest electrical conductivity of the following aqueous solutions is of

What sized ring is formed when two carboxylic acids form a dimeric structure through intermolecular hydrogen bonding? (Consider the hydrogen bond as a bond in the ring structure.)

Reducing property of formic acid is due to the presence of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The product $P$ in the following reaction is:$PhCHO + (CH_3CH_2CO)_2O \xrightarrow{CH_3CH_2COONa \text{ (anhydrous)}} P$