The quadratic equation 2x^{2} - sqrt{5}x + 1 | vedclass

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(B) Given equation is $2x^{2} - \sqrt{5}x + 1 = 0$.On comparing with the standard form $ax^{2} + bx + c = 0$,we get:$a = 2, b = -\sqrt{5}, c = 1$.The

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no real roots

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(B) Given equation is $2x^{2} - \sqrt{5}x + 1 = 0$.On comparing with the standard form $ax^{2} + bx + c = 0$,we get:$a = 2, b = -\sqrt{5}, c = 1$.The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.Substituting the values:$D = (-\sqrt{5})^{2} - 4(2)(1) = 5 - 8 = -3$.Since the discriminant $D < 0$,the quadratic equation has no real roots (i.e.,it has imaginary roots).

The quadratic equation $2x^{2} - \sqrt{5}x + 1 = 0$ has

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