The radii of F, F^{-}, O and O^{2-} are in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The size of an atom or ion depends on the effective nuclear charge and the number of shells.For isoelectronic species $(O^{2-}, F^{-})$,the specie

Vedclass · Accepted Answer

$O^{2-} > F^{-} > O > F$

Vedclass · Answer

(A) The size of an atom or ion depends on the effective nuclear charge and the number of shells.For isoelectronic species $(O^{2-}, F^{-})$,the species with the lower nuclear charge has a larger radius. Since $O$ $(Z=8)$ has a lower nuclear charge than $F$ $(Z=9)$,$O^{2-}$ is larger than $F^{-}$.Comparing neutral atoms,$O$ $(Z=8)$ is larger than $F$ $(Z=9)$ due to the decrease in atomic radius across a period.Furthermore,an anion is always larger than its parent neutral atom due to increased inter-electronic repulsion and decreased effective nuclear charge per electron.Therefore,the correct order of radii is $O^{2-} > F^{-} > O > F$.Hence,option $A$ is correct.

The radii of $F, F^{-}, O$ and $O^{2-}$ are in the order of :-

Similar Questions

Which of the following has the largest ionic radius?

The element expected to form the largest ion to achieve the nearest noble gas configuration is

Identify the correct order of the ionic size for the following isoelectronic species:

Which of the following atoms has the smallest atomic size?

Which of the following is the correct increasing order of ionic radii for $Na, Rb, K,$ and $Mg$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module