The radii of a frustum of a cone are 10,cm an | vedclass

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(C) For the frustum of a cone, the slant height $l$ is given by the formula:$l = \sqrt{h^2 + (r_1 - r_2)^2}$Given $h = 4\,cm$, $r_1 = 10\,cm$, and $r_

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$85$

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(C) For the frustum of a cone, the slant height $l$ is given by the formula:$l = \sqrt{h^2 + (r_1 - r_2)^2}$Given $h = 4\,cm$, $r_1 = 10\,cm$, and $r_2 = 7\,cm$:$l = \sqrt{4^2 + (10 - 7)^2} = \sqrt{16 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\,cm$The curved surface area $(CSA)$ of a frustum of a cone is given by:$CSA = \pi l(r_1 + r_2)$Substituting the values:$CSA = \pi 	imes 5 	imes (10 + 7) = \pi 	imes 5 	imes 17 = 85\pi\,cm^2$

The radii of a frustum of a cone are $10\,cm$ and $7\,cm$. If its height is $4\,cm$, then its curved surface area is $\ldots \ldots \ldots \,cm^2$. (in $\pi$)

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