The radius of a circular ground is $63 \, m$. Find the cost of fencing its boundary at the rate of ₹ $50 / m$. Find the cost of levelling the ground at the rate of ₹ $40 / m^2$.
(N/A) $1$. Cost of fencing: The boundary of the circular ground is its circumference,given by $C = 2 \pi r$.
Using $r = 63 \, m$ and $\pi = 22/7$,we get $C = 2 \times (22/7) \times 63 = 2 \times 22 \times 9 = 396 \, m$.
The cost of fencing is $396 \, m \times ₹ 50/m = ₹ 19,800$.
$2$. Cost of levelling: The area of the circular ground is $A = \pi r^2$.
$A = (22/7) \times 63 \times 63 = 22 \times 9 \times 63 = 12,474 \, m^2$.
The cost of levelling is $12,474 \, m^2 \times ₹ 40/m^2 = ₹ 4,98,960$.
Using $r = 63 \, m$ and $\pi = 22/7$,we get $C = 2 \times (22/7) \times 63 = 2 \times 22 \times 9 = 396 \, m$.
The cost of fencing is $396 \, m \times ₹ 50/m = ₹ 19,800$.
$2$. Cost of levelling: The area of the circular ground is $A = \pi r^2$.
$A = (22/7) \times 63 \times 63 = 22 \times 9 \times 63 = 12,474 \, m^2$.
The cost of levelling is $12,474 \, m^2 \times ₹ 40/m^2 = ₹ 4,98,960$.
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