The radius of an atom is of the order of 1,ma | vedclass

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(B) Radius of atom $R_{1} = 1\,\mathring{A} = 10^{-10}\,	ext{m}$.Radius of nucleus $R_{2} = 1\,	ext{fermi} = 10^{-15}\,	ext{m}$.Volume of atom $V_{

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$10^{15}$

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(B) Radius of atom $R_{1} = 1\,\mathring{A} = 10^{-10}\,	ext{m}$.Radius of nucleus $R_{2} = 1\,	ext{fermi} = 10^{-15}\,	ext{m}$.Volume of atom $V_{1} = \frac{4}{3} \pi R_{1}^{3}$.Volume of nucleus $V_{2} = \frac{4}{3} \pi R_{2}^{3}$.The ratio of the volumes is given by $\frac{V_{1}}{V_{2}} = \frac{\frac{4}{3} \pi R_{1}^{3}}{\frac{4}{3} \pi R_{2}^{3}} = \left(\frac{R_{1}}{R_{2}}ight)^{3}$.Substituting the values: $\frac{V_{1}}{V_{2}} = \left(\frac{10^{-10}}{10^{-15}}ight)^{3} = (10^{5})^{3} = 10^{15}$.Thus,the volume of the atom is $10^{15}$ times larger than the volume of the nucleus.

The radius of an atom is of the order of $1\,\mathring{A}$ and the radius of a nucleus is of the order of $1$ fermi. How many magnitudes higher is the volume of the atom as compared to the volume of the nucleus?

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