The radius of the bore of a capillary tube is $r$ and the angle of contact of the liquid is $\theta$. When the tube is dipped in the liquid,the radius of curvature of the meniscus of liquid rising in the tube is

  • A
    $r \sin \theta$
  • B
    $\frac{r}{\sin \theta}$
  • C
    $r \cos \theta$
  • D
    $\frac{r}{\cos \theta}$

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