Two capillary tubes of same diameter are kept vertically in two liquids whose densities are in the ratio $4:3$. If their surface tensions are in the ratio $6:5$,the ratio of heights $\left(\frac{h_1}{h_2}\right)$ of liquids in the two capillary tubes is (Their angle of contacts are same).

$A$ capillary tube,when immersed vertically in a liquid,records a rise of $3 \, cm$. If the tube is immersed in the liquid at an angle of ${60^\circ}$ with the vertical,what is the length of the liquid column along the tube in $cm$?

$A$ uniform capillary tube of length $l$ and inner radius $r$ with its upper end sealed is submerged vertically into water. The outside pressure is $p_{0}$ and surface tension of water is $\gamma$. When a length $x$ of the capillary is submerged into water, it is found that water levels inside and outside the capillary coincide. The value of $x$ is

In an experiment to find the surface tension of mercury with the help of the capillary rise method,the liquid column in the capillary will:

The heat evolved for the rise of water when one end of the capillary tube of radius $r$ is immersed vertically into water is (Assume surface tension $= T$ and density of water to be $\rho$)

When a capillary tube is kept in water, water $......$ in the capillary, while when it is kept in mercury, the mercury $......$ in the capillary. (Choose the correct words: $rising up$ / $depressed$)