The radius of the circle passing through the point $(6, 2)$ and whose two diameters are $x + y = 6$ and $x + 2y = 4$ is

The abscissae of two points $A$ and $B$ are the roots of the equation $x^2+2ax-b^2=0$ and their ordinates are roots of the equation $y^2+2py-q^2=0$. Then the equation of the circle with $AB$ as diameter is given by

If $(4,7)$ and $(-2,-1)$ are ends of a diameter of a circle which intersects $X$-axis at $A$ and $B$,then $AB$ is equal to

$A$ circle touches the axes at the points $(3, 0)$ and $(0, -3)$. The centre of the circle is

The equation of the circle passing through the points $(1, \sqrt{2})$,$(7, \sqrt{2})$,and $(1, 3)$ is:

The equation of the circle with centre $(2, -3)$ and touching the $X$-axis is