The radius of the light circle observed by a | vedclass

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(B) When a fish is at a depth $h$ below the surface of water, it sees the outside world through a circular window due to total internal reflection.The

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$\frac{36}{\sqrt{7}}$

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(B) When a fish is at a depth $h$ below the surface of water, it sees the outside world through a circular window due to total internal reflection.The radius $r$ of this circle is given by the formula $r = \frac{h}{\sqrt{\mu^2 - 1}}$.Given: depth $h = 12 \ m$ and refractive index $\mu = 4/3$.Substituting the values into the formula:$r = \frac{12}{\sqrt{(4/3)^2 - 1}}$$r = \frac{12}{\sqrt{16/9 - 1}}$$r = \frac{12}{\sqrt{7/9}}$$r = \frac{12 	imes 3}{\sqrt{7}}$$r = \frac{36}{\sqrt{7}} \ m$.

The radius of the light circle observed by a fish at a depth of $12 \ m$ is (refractive index of water $\mu = 4/3$):

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