The rate constant for the reaction,$2N_2O_5 \to 4NO_2 + O_2$ is $3 \times 10^{-5} \, s^{-1}$. If the rate is $2.40 \times 10^{-5} \, mol \, L^{-1} \, s^{-1}$,then the concentration of $N_2O_5$ (in $mol \, L^{-1}$) is

  • A
    $1.4$
  • B
    $1.2$
  • C
    $0.04$
  • D
    $0.8$

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The given data are for the reaction:
$2NO_{(g)} + Cl_{2(g)} \to 2NOCl_{(g)}$ at $298 \ K$
Experiment$[Cl_2] \ (M)$$[NO] \ (M)$Rate $(mol \ L^{-1} \sec^{-1})$
$I$$0.05$$0.05$$1 \times 10^{-3}$
$II$$0.15$$0.05$$3 \times 10^{-3}$
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The rate law for the reaction is:

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