The ratio between the $RMS$ velocity of $N_2$ at $200 \ K$ and that of $CO$ at $800 \ K$ is (molecular mass of $N_2 = 28 \ g \ mol^{-1}$, molecular mass of $CO = 28 \ g \ mol^{-1}$)

The following graph is obtained for a gas at different temperatures $T_1$,$T_2$,$T_3$. What is the correct order of temperature? ($x$-axis $=$ velocity; $y$-axis $=$ number of molecules)

Initially,the root mean square $(rms)$ velocity of $N_2$ molecules at a certain temperature is $u$. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms,then the new $rms$ velocity will be:

$A$ $50 \, L$ container holds $0.5 \, mol$ of $O_2$ gas at $27 \, ^oC$ and $2 \, atm$ pressure. If half of the $O_2$ molecules are removed from the container,what happens to the $rms$ speed of the $O_2$ molecules?

At what temperature will the $RMS$ velocity of $SO_2$ be the same as that of $O_2$ at $303 \ K$?

Explain the speed of molecules of a gas and the average speed $(u_{av})$.