The ratio of the average electric energy density to the total average energy density of an electromagnetic wave is:

  • A
    $2$
  • B
    $1$
  • C
    $3$
  • D
    $\frac{1}{2}$

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Similar Questions

Identify the correct statements from the following descriptions of various properties of electromagnetic waves.
$A$. In a plane electromagnetic wave,the electric field and magnetic field must be perpendicular to each other,and the direction of propagation of the wave should be along the electric field or magnetic field.
$B$. The energy in an electromagnetic wave is divided equally between the electric and magnetic fields.
$C$. Both the electric field and magnetic field are parallel to each other and perpendicular to the direction of propagation of the wave.
$D$. The electric field,magnetic field,and direction of propagation of the wave must be mutually perpendicular to each other.
$E$. The ratio of the amplitude of the magnetic field $(B_0)$ to the amplitude of the electric field $(E_0)$ is equal to the reciprocal of the speed of light $(1/c)$.
Choose the most appropriate answer from the options given below:

Electromagnetic waves of frequency $8.196 \times 10^6 \ Hz$ are propagating from a source. What is the wavelength of these electromagnetic waves in $cm$?

The velocity of an electromagnetic wave is parallel to:

$A$ laser beam has intensity $17.7 \times 10^{14} \ W/m^2$. The amplitude of the electric field is
[Use $\epsilon_0 = 8.85 \times 10^{-12} \ C^2 / (N \cdot m^2)$]

Radio waves and visible light in vacuum have

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